
Contributor
•
3 Messages
What about loyal customers
your company is always offering deals to new customers. I have been a loyal customer for almost 20 years. I did not jump back and forth between companies, who ever had the best deal, or offered the best phone- I have been a loyal customer. When I contacted at&t about your deal, buy one get one free I was ineligible. I want to know-does loyalty not matter anymore?
ATTHelp
Community Support
•
225K Messages
4 years ago
Hello, @KrisKris,
We do appreciate our long term loyal customers. Thank you. We have AT&T Thanks to provide lagniappe for our customers. There's always several gifts you can put in for. the long running Ticket Tuesday is a favorite and you can get a discount at several restaurants using AT&T Thanks just for being an AT&T Customer. Add the AT&T Thanks app and see what you can receive.
Have a great week!
James, AT&T Community Specialist
0
0
formerlyknownas
ACE - Sage
•
113.3K Messages
4 years ago
@KrisKris
ATTCares can only give you a polite response. As a fellow customer, I can add facts and just say, “you’re asking too much”. Switching is expensive under the best circumstances.
Realistically, no carrier can offer deals like BOGO to everyone. AT&T has 147 million postpaid connections. Even offering everyone $100 off each upgrade would cost 14.7 billion dollars. Carriers have stock holders they must report their actions to.
And you can’t argue, “what about just long time customers?” How long? And how many are there? Are people with 20 years long enough, but 19 not long enough?
As for those deals; They are a lost leader to gain new business and make a profit, they are not to save the new customer money.
Prices on current plans have been reduced to service only. All plans since the Mobile Share Value plan are service only. Plans older than that included phones in cost of service.
0
0
TROLLEDYOUSO
Guru
•
561 Messages
4 years ago
Think of it this way: New customers get ONE nice thing. Then they become existing customers and are mistreated like everybody else.
0
0